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56b^2+17b-3=0
a = 56; b = 17; c = -3;
Δ = b2-4ac
Δ = 172-4·56·(-3)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-31}{2*56}=\frac{-48}{112} =-3/7 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+31}{2*56}=\frac{14}{112} =1/8 $
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